1047A - Little C Loves 3 I - CodeForces Solution


math *800

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Python Code:

n=int(input())
if n%3==2:print(2,2,n-4)
else:print(1,1,n-2)

C++ Code:

#include<bits/stdc++.h>
using namespace std;
int main()
{
	int n;
	scanf("%d",&n);
	if((n-2)%3)printf("1 1 %d",n-2);
	else printf("1 2 %d",n-3);
}


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